Question Description

Final Answer

6.022 *10^23 molecules of aspirin contain 180.157 g of aspirin
No: of molecules of aspirin in 0.1 g = 180.157 *0.1/6.022 *10^23
= 2.99 *10^-23 or 3 * 10^-23 molecules
Please let me know if you have any questions and best me if you are satisfactory.
