Fe3O4(s) + 4H2(g)3Fe(s) + 4H2O(g) H° = 151.2 kJ and S° = 169.4 J/K The standar

Jun 10th, 2015
DreamIt
Category:
Chemistry
Price: \$5 USD

Question description

Fe3O4(s) + 4H2(g)3Fe(s) + 4H2O(g)

H° = 151.2 kJ and S° = 169.4 J/K

The standard free energy change for the reaction of 1.89 moles of Fe3O4(s) at 346K, 1 atm would be  kJ.

This reaction is (reactant, product)  favored under standard conditions at 346 K.

Assume that H° and S° are independent of temperature.

(Top Tutor) Daniel C.
(997)
School: UCLA

Studypool has helped 1,244,100 students

Review from our student for this Answer

FratBro23
Jun 11th, 2015
"all I can say is wow very fast work, great work thanks"

1820 tutors are online

Brown University

1271 Tutors

California Institute of Technology

2131 Tutors

Carnegie Mellon University

982 Tutors

Columbia University

1256 Tutors

Dartmouth University

2113 Tutors

Emory University

2279 Tutors

Harvard University

599 Tutors

Massachusetts Institute of Technology

2319 Tutors

New York University

1645 Tutors

Notre Dam University

1911 Tutors

Oklahoma University

2122 Tutors

Pennsylvania State University

932 Tutors

Princeton University

1211 Tutors

Stanford University

983 Tutors

University of California

1282 Tutors

Oxford University

123 Tutors

Yale University

2325 Tutors