Please help with biology question!

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Jun 10th, 2015

Thank you for the opportunity to help you with your question!

i think is a X linked , female gets one X from her mom and one X from dad , so when her DAD's X is dominant means it may occur.

X is consider be the chromosome for Hypophosphatemia

If male having Hypophosphatemia

Xy * Female xx =>F1 Xx Xx xy xy

now the daughter has Xx Hypophosphatemia cross with

Xx * xy => Xx Xy xx xy

50% of population having the Hypophosphatemia

I cant draw a punnet square on here but if you imagine that the mother has the genotype Ee as she is a carrier. The father has the genotype E/ as he only has one X chromosome and it is unaffected.

There are three possible genotypes for the children...

EE ........ Ee ........ E / ........ e /

Female ..... Female .... Male ...... Male affected

Unaffected ....Carrier.... .Unaffected..... .

So you have a one in four chance (25%) that the child will inherit the disorder, the probability that the child will not inherit the e allele, is one in two, or 50%.

The pattern of inheritance on a sex linked (recessive) trait is that it is usually seen in males, even if both parents are unaffected.

It is only seen in females if the father has the disease, as she must recieve an X chromosome from him.

It cannot be passed from an unaffected father to a son, so if a son has the disease and the father does not then the defective allele must have come from the mother, who is by definiton a carrier.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 10th, 2015

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