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i think is a X linked , female gets one X from her mom and one X from dad , so when her DAD's X is dominant means it may occur.X is consider be the chromosome for HypophosphatemiaIf male having HypophosphatemiaXy * Female xx =>F1 Xx Xx xy xynow the daughter has Xx Hypophosphatemia cross withXx * xy => Xx Xy xx xy50% of population having the HypophosphatemiaI cant draw a punnet square on here but if you imagine that the mother has the genotype Ee as she is a carrier. The father has the genotype E/ as he only has one X chromosome and it is unaffected.There are three possible genotypes for the children...EE ........ Ee ........ E / ........ e /Female ..... Female .... Male ...... Male affectedUnaffected ....Carrier.... .Unaffected..... .So you have a one in four chance (25%) that the child will inherit the disorder, the probability that the child will not inherit the e allele, is one in two, or 50%.The pattern of inheritance on a sex linked (recessive) trait is that it is usually seen in males, even if both parents are unaffected.It is only seen in females if the father has the disease, as she must recieve an X chromosome from him.It cannot be passed from an unaffected father to a son, so if a son has the disease and the father does not then the defective allele must have come from the mother, who is by definiton a carrier.
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