The concentration of carbon monoxide in an urban apartment is 49 µg/m3. What mass of carbon monoxide in grams is present in a room measuring 8 ✕ 12 ✕ 22 ft? (Enter your answer to three digits.)
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Concentration of CO= 49μg/m3
Volume of room = 8*12*22= 2112ft3
Mass of CO in grams=?
35.3417ft3 = 1m3
2112ft3 = (1m3
1m3 of the room has 49μg
= 2930.445μg CO
106μg = 1g
2930.445 μg = (1*2930.445)/106
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