A cook holds a 2.59-kg carton of milk at arm's length (see the figure below). What force vector F B must be exerted by the biceps muscle? (Ignore the weight of the forearm. State the magnitude of the force vector F B.)
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post the picture too..............i don't want to answer the wrong thing
The torques created by the weights are clockwise relative to the pivot, while the torque created by the biceps is counterclockwise; thus, the second condition for equilibrium (netτ=0) becomes
Note that sinθ=1 for all forces, since θ=90º for all forces. This equation can easily be solved for FB in terms of known quantities, yielding
Entering the known values gives
Now, the combined weight of the arm and its load is (6.50 kg)(9.80m/s2)=63.7 N, so that the ratio of the force exerted by the biceps to the total weight is
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