# A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is fre

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### Question Description

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 230 N applied to its edge causes the wheel to have an angular acceleration of 0.818 rad/s2

(a) What is the moment of inertia of the wheel?

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(1) τ = Iα
(2) τ = rF

Substituting (2) into (1):

rF = Iα

Solved for I:

I = rF / α
= 62.1 kg∙m²

Then, the moment of inertia for a solid uniform cylinder is:

I = 0.5mr²
m = 2I / r²
= 2(62.1kg∙m²) / (0.330m)²
= 1141kg

Sngva Zraunm (1755)
Boston College
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Anonymous
I was having a hard time with this subject, and this was a great help.

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