A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 230 N applied to its edge causes the wheel to have an angular acceleration of 0.818 rad/s2.
Thank you for the opportunity to help you with your question!
(1) τ = Iα (2) τ = rF Substituting (2) into (1): rF = Iα Solved for I: I = rF / α = (0.330m)(230N) / 0.818rad/s² = 62.1 kg∙m² Then, the moment of inertia for a solid uniform cylinder is: I = 0.5mr² m = 2I / r² = 2(62.1kg∙m²) / (0.330m)² = 1141kg
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?