Systems of Euations word problem.

label Algebra
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schedule 1 Day
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The sum of three numbers is 98. The sum of the first and second is two more than the third number and the second is four times the first. Find the numbers?

Jun 11th, 2015

Thank you for the opportunity to help you with your question!

let the numbers be ;x ,y z

x+y+z=98-----------------i

x+y+2=z------------------ii

4x=y----------------------iii

or 4x-y=0

then solve

x+y+z=98

x+y-z=-2

Add equations i and ii to obtain iii

2x+2y=96------------------iv

using iii and iv

2x+2y=96

(4x-y=0)2=8x-2y=0

Add the two equations

2x+2y=96

+

8x-2y=0

10x=96

x =9.6

y=2.4

z=86



Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 11th, 2015

CORRECTION PLEASE CHECK

Thank you for the opportunity to help you with your question!

let the numbers be ;x ,y z

x+y+z=98-----------------i

x+y-2=z------------------ii

4x=y----------------------iii

or 4x-y=0

then solve

x+y+z=98

x+y-z=2

Add equations i and ii to obtain iii

2x+2y=100------------------iv

using iii and iv

2x+2y=100

(4x-y=0)2=8x-2y=0

Add the two equations

2x+2y=100

+

8x-2y=0

10x=100

x =10

y=40

z=98-(40+10)

z=48


Jun 11th, 2015

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