M(t)= -2.45t^2+31.65t+346.5

a.) In what year was the clubs membership at its highest?

b.) how many members did the club have at the peak?

Thank you for the opportunity to help you with your question!

The maximum is achieved for t as M'(t)=0

M'(t)=-4.90t+31.65

M'(t)=0 <=> -4.90t+31.65 <=> t=31.65/4.90=6.45=Tmax

The number of members is at its highest on the 6th year wich corresponds to 2010

M(Tmax)=448.7, the number of members should be 449 members.

how did you do this? what did you plug into the calc?

Do you mean for a or b

?

For a, you should calculate the derivative function M'(t), did you learn derivative functions ?

both

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