2002, and 2004 had over 400 members. Suppose the club price from 2004 to 2014 is described

label Mathematics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

M(t)= -2.45t^2+31.65t+346.5 

a.) In what year was the clubs membership at its highest? 

b.) how many members did the club have at the peak?

Jun 11th, 2015

Thank you for the opportunity to help you with your question!

M(t)= -2.45t^2+31.65t+346.5 

The maximum is achieved for t as M'(t)=0 

M'(t)=-4.90t+31.65 

M'(t)=0 <=> -4.90t+31.65 <=> t=31.65/4.90=6.45=Tmax

The number of members is at its highest on the 6th year wich corresponds to 2010

M(Tmax)=448.7, the number of members should be 449 members. 


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 11th, 2015

how did you do this? what did you plug into the calc?

Jun 11th, 2015

Do you mean for a or b

?


Jun 11th, 2015

For a, you should calculate the derivative function M'(t), did you learn derivative functions ? 

Jun 11th, 2015

both

Jun 11th, 2015
Jun 11th, 2015

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