Thank you for the opportunity to help you with your question!
Let UNITs guide you; always USE THEM in your calculation to prevent errors
Firstly, the eqn: I- (aq) + I2 (aq) -----> I3- (aq); K = 710 L/mol
K = [i3-]/([i2][i-])
5.00E-2 mol I2 +1.00 liters 5.00E-1 M KI
[KI]init = 5.00E-1 moles/liter
[I2]init = 5.00E-2 moles/liter
[KI]eq = 5.00E-1 moles/liter - x moles/liter
[I2]eq = 5.00E-2 moles/liter - x moles/liter
[I3-]eq = x moles/liter
K= 710 liters/mole = (x moles/liter) / [5.00E-1 - x moles/liter)(5.00E-2 - x moles/liter)]
SOLVE for x
[I3-]/[I2] = x moles I3- / (5.00E-2 - x moles/liter) I2 = ??
Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem. Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 13th, 2015
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