 # Preparation of a complex iron salt

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zbagery

Science

### Question Description

calculate the number of grams (theoretical yield)of the final iron complex that can be produced from 10.00 g of ferrous ammonium sulfate hexahydrate Student has agreed that all tutoring, explanations, and answers provided by the tutor will be used to help in the learning process and in accordance with Studypool's honor code & terms of service. this is the chemical euaqtion for preparation of salt

2Fe(NH4)2(SO4)2 * 6H2O(aq) + 3H2C2O4(aq) + H2O2(aq) + 3K2C2O4(aq) ----- 2K3Fe(C2O4)3 *

+ 3H2O(s) + 8H2O(L) + 2(NH4)2SO4(aq) + 2H2SO4(aq)

Look at the equation: 2 moles complex reactant produces 2 moles complex product.

The number of moles of the product will be the same as the number of moles reactant.

moles reactant = mass / molar mass = 10 g / 284.049 g/mol = 0.0252.

mass product = moles * molar mass = 0.0252 mol * 491.2 g/mol = 12.378 = 12.38 g.

so the number of grams (theoretical yield)of the final iron complex that can be produced from 10.00 g of ferrous ammonium sulfate hexahydrate is 12.38 gram. qnex xavtug (29)
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