-0.01x^2+0.6x+6.5 distance of the throw

Algebra
Tutor: None Selected Time limit: 1 Day

an athlete whose event in shot put releases a shot. when the shot is released at an angel of 30 degrees, it's height, f(x), in feet, can be modeled by f(x)=-0.01x^2+0.6x+6.5, where x is the shot's horizontal distance, in feet, from its point of release. 

what is the show's maximum horizontal distance to the nearest tenth of a foot, or distance of the throw?

Jun 13th, 2015

Thank you for the opportunity to help you with your question!

to find the maximum we have to convert the polynomial into

following form

f(x)=-0.01(x^2-60x-650)

f(x)=-0.01[(x-30)^2-900-650]

f(x)=-0.01[(x-30)^2-1550]

to find max distance (x-30)^2 should goes to zero

then 

f(x)max=-0.01(0-1550)

=15.5 feet

so max height =15.5 feet



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Jun 13th, 2015

yes, but what is the shot's maximum horizontal distance/distance of the throw in feet?

Jun 13th, 2015

oh i'm sorry.

the max horizontal distance also equal to max height=15.5 feet

Jun 13th, 2015

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Jun 13th, 2015
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