an athlete whose event in shot put releases a shot. when the shot is released at an angel of 30 degrees, it's height, f(x), in feet, can be modeled by f(x)=-0.01x^2+0.6x+6.5, where x is the shot's horizontal distance, in feet, from its point of release.

what is the show's maximum horizontal distance to the nearest tenth of a foot, or distance of the throw?

Thank you for the opportunity to help you with your question!

to find the maximum we have to convert the polynomial into

following form

f(x)=-0.01(x^2-60x-650)

f(x)=-0.01[(x-30)^2-900-650]

f(x)=-0.01[(x-30)^2-1550]

to find max distance (x-30)^2 should goes to zero

then

f(x)max=-0.01(0-1550)

=15.5 feet

so max height =15.5 feet

hope you happy with my answer please don't forget to rate me and leave a comment.if you have any question please let me know i'll choose the best answer for you.thank you.see you soon again...:)

Please let me know if you need any clarification. I'm always happy to answer your questions.