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tbqtvey14

Science

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Calculate the concentration of H3O+ in 0.120M hippuric acid given the pKa is 3.62

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Explanation & Answer

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First we need to write the chemical reaction that occurs when the acid dissociates. HC9H8NO3 ---> C9H8NO3- H We can write an equilibrium expression for this reaction, products/reactants. K = [C9H8NO3-] [H ] / [HC9H8NO3] Now, we need to think about what is happening during dissociation. We start out with a certain concentration of the acid. thus, when it dissociates it loses concentration. lets say it loses x amount of concentration. so if the initial concentration of the acid is 0.120M, then at equilibrium it will be 0.120 - x. Now, when it dissociates, the products gain concentration.


Since  pKa = -log pKa

Ka = 24 * 10 -5

HC9H8NO3 = H3O C9H8NO3 0.12-x x x Ka = x 2 /(0.12-x) x 2 24 *10 -5 x - 4.56* 10 -5 =0

After solving the equation x = 6.634*10 -3 M

Conc. of H30 =6.634*10 -3 M

Please let me know if you need any clarification. I'm always happy to answer your questions.


Anonymous
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