The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm.
Thank you for the opportunity to help you with your question!
S = 4*pi*r^2
delta S = 8*pi*r delta r = 8*pi*76*0.5 = 955 cm^2
relative error = dela S/S = 8 pi*r*deltar / (4*pi*r^2) = 2delta r/r = 1/76 = 0.013
b) V= 4/3 pi*r^3
dV = 4pir^2 dr = 4*pi*76^2 *0.5 = 36292
relative error = 4pi r^2 dr / (4/3*pir^3) = 3dr/r = 1.5/76 = 0.020
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?