In a Box of chocolates, there are 8 pieces you like and 4 you don't. Suppose you chose 3 of them.

A.) what is the probability you don't like all 3=0.018

B.)What is the probability you like atleast one?=0.9629

C.) What is the probability get atleast one you don't like?

I tried the compliment rule I was wrong

Thank you for the opportunity to help you with your question!

total number of items=8+4=12

A=0.018

B =0.9629

..................................................................

May I know how you got that?

In B.) I did this 1-(4/12)^=0.92629, so I figured it be the same but with ones

I didn't like? It seems too simple, maybe I'm over thinking the formulas

I forgot the ^3

1-(4/12)^3

1-(1/3)^3

1-(0.03704)^3

=0.9999

Thankyou

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