second one, please show all the work

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anllre2130r

Mathematics

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Explanation & Answer

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Ok thanks a lot man.


given x ->0  [ 1/r + 1/x-r ] / x

so for your understanding  first take  1/r  + 1/x-r  and simplify

1/r  + 1/x-r  =   [ x-r +r ] / (r) * (x-r)

                  =  x / (r) * (x-r)


now plug it in the actual problem   x -->0    x / (r) * (x-r) *x

in the numerator and denominator we have x , so both will get cancel

 x ->0  [ 1/r + 1/x-r ] / x  =   1 / (r) * (x-r)

so now plug x =0

we will get      =  1 / (r) * (0 -r)

                       =  1 / ( r) * (-r)

                       = - 1 /  (r^2)



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qnex xavtug (29)
UT Austin

Anonymous
Just the thing I needed, saved me a lot of time.

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