second one, please show all the work

Calculus
Tutor: None Selected Time limit: 1 Day

Jun 14th, 2015

Thank you for the opportunity to help you with your question!

Ok thanks a lot man.


given x ->0  [ 1/r + 1/x-r ] / x

so for your understanding  first take  1/r  + 1/x-r  and simplify

1/r  + 1/x-r  =   [ x-r +r ] / (r) * (x-r)

                  =  x / (r) * (x-r)


now plug it in the actual problem   x -->0    x / (r) * (x-r) *x

in the numerator and denominator we have x , so both will get cancel

 x ->0  [ 1/r + 1/x-r ] / x  =   1 / (r) * (x-r)

so now plug x =0

we will get      =  1 / (r) * (0 -r)

                       =  1 / ( r) * (-r)

                       = - 1 /  (r^2)



I hope understand it well. If not comment but don't forget to rate me and give me more and more questions. thanks

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 14th, 2015

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