Thank you for the opportunity to help you with your question!

Ok thanks a lot man.

given x ->0 [ 1/r + 1/x-r ] / x

so for your understanding first take 1/r + 1/x-r and simplify

1/r + 1/x-r = [ x-r +r ] / (r) * (x-r)

= x / (r) * (x-r)

now plug it in the actual problem x -->0 x / (r) * (x-r) *x

in the numerator and denominator we have x , so both will get cancel

x ->0 [ 1/r + 1/x-r ] / x = 1 / (r) * (x-r)

so now plug x =0

we will get = 1 / (r) * (0 -r)

= 1 / ( r) * (-r)

= - 1 / (r^2)

I hope understand it well. If not comment but don't forget to rate me and give me more and more questions. thanks

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