Math Question For Algebra

Mathematics
Tutor: None Selected Time limit: 1 Day

If a ball is thrown upward at 64 ft per second from a height of 12 ft, the height of the ball can be modeled by S=12=64t-16^2, where t is the number of seconds after the ball is thrown. how long after the ball is thrown is the height 40 ft?

Jun 14th, 2015

Thank you for the opportunity to help you with your question!

v1= 64 feet per second [up]
a= 9.81 m/s2 [down]= -9.81 m/s2 [up] = -32.185 feet/s2 [down] (1 metre= 3.28083989501312 feet)
t= 3s
d= ?

Step 2
Solve:

d= v1t+(1/2)at2
d= 64(3)+(1/2)(-32.185)(3)2
d= 192-144.8325
d= 47.165 feet

*Remember you need to add the initial height

d=12+47.165
d=59.1675 feet= 10 feet

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 14th, 2015

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