Consider the following algorithm

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Mathematics

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60 + operations.

there are two for loops under 'i'

i for loop will run 4 times.

j will run for 3 times, therefore total (4*3)= 12 '+'operations

k will run for 6 times, therefore total (4*6)=24

since, there are two statements under 'k' for loop. total '+' operations=24 + 24=48


j+k= 12+48=60


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trrxpbqr (70)
UT Austin

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