Find the third term of the sequence given by the rule tn=2 (3)^n-1

Algebra
Tutor: None Selected Time limit: 1 Day

A.54 B.18 C.27 D.9

Jun 15th, 2015

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tn=2 (3)^n-1

third term , when n=3

t3 = 2(3)^3-1

t3 = 2(3)^2

t3 = 2(9)

t3 = 18

ans = B= 18

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Jun 15th, 2015

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