What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)?
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point slope form is (y-y1) = m(x-x1) where m is the slope and x1,y1 is a point on the line.
We need to find the slope first which is given by
m =( y2-y1 ) /(x2 - x1)
We have two points (x1,y1) = (4,0) and (x2,y2) = (2,6)
m = (6 -0 ) / (2-4) = 6/-2 = -3
substituting m = -3 and (x1,y1) = (4,0) in slope point form
The equation in the slope point form will be
y-0 = -3 (x-4)
y = -3(x-4) choice 3
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