Find and equation of the line that satisfies the given condition

Algebra
Tutor: None Selected Time limit: 1 Day

through (1, -9) parrallel to x+2y=6 please show steps

through (-2, 4) parrallel to the line x=5 please show steps

through (-1,-2) parrallel to the line passing through (5,5) and (1,1)

Jun 17th, 2015

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 y= mx+ c is the Eq of line in slope intercept form ...

1.  line x +2y = 6    can be written as   y = -1/2 x+3      hence  slope of parallel line = -1/2 =-0.5

y = -0.5x+c  ; line is passing through (1,-9) hence -9 =-0.5*1+c ; solving we get c = -8.5

hence the equation become y = -0.5x-8.5   ; or x+2y+17=0

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2.  line x = 5  is a line parallel to y axis hence  slope of parallel line = infinity   or (1/0)

y = (1/0) x+c  ; line is passing through (-2,4) hence  4 =(1/0) * -2+c ; solving we get c = 2

hence the equation become x = -2  ; or x = -2

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3.  slope of parallel line = (5-1)/(5-1) = 1

y = (1) x+c  ; line is passing through (-1,-2) hence  -2 =(1) * -1+c ; solving we get c = -1

hence the equation become y=x-1  ; or x-y = 1


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Jun 17th, 2015

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