If this reaction produced 32.5g of KCl, how much O2 was produced in grams

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2KClO3 2KCl + 3O2

Jun 17th, 2015

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(32.5 g KCl) / (74.5 g KCl/mol)=0.436 mol

2:3=0.436:x

x=3*0.436/2=0.654 mol

(0.654mol)*(32g O2/mol)=20.9 g O2

Answer: 20.9 g O2

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Jun 17th, 2015

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