A 500-N tightrope walker stands at the center of the rope. If the rope can withstand a tension of 1 800 N without breaking, what is the minimum angle the rope can make with the horizontal?

Thank you for the opportunity to help you with your question!

considering the equlibrum

lets get the minimum angle as X

then

2*1800 sin(X)=500

sin X=500/3600

sin (X)=5/36

X=sin^-1(5/36)

X=7.98

so minimum angle is 7.98

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