A car is initially moving at 20 m/s east, and a little while later it is moving

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A car is initially moving at 20 m/s east, and a little while later it is moving at 10 m/s north. Which of the following best describes the orientation of the average acceleration during this time interval?

a.
b.
c.
d.
Oct 18th, 2017

Thank you for the opportunity to help you with your question!

Conceptually speaking the direction of change in velocity, which will also be direction of average acceleration must have component along West to neutralize its motion along east and must also have component along North in order to finally move in that direction. Mathematically draw the initial, V1 and final vector, V2. Apply Triangle law of addition/subtraction to get the direction of the vector, V2 - V1 and see that it has direction of tan^-1( 2) = 63.4 degree,. Please note that average acceleration = (V2 - V1)/t, where t is time interval. 


something has to stop it going east, so the a is west and to go north you need an a value north

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 18th, 2015

so, what is the answer


Jun 18th, 2015

northwest

Jun 18th, 2015

are you sure?

cuz i had answer A 


Jun 18th, 2015

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Oct 18th, 2017
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Oct 18th, 2017
Oct 19th, 2017
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