Let t4 + 10t2 + 4 = 2t2 - 3. Solve for t.

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t^4 + 10t^2 + 4 = 2t^2 - 3

t^4+10t^2-2t^2+7=0

t^4+8t^2+7=0

Factorise

(t^2+1)(t^2+7)=0

therefore t^2+1=0

t^2=-1

taking square root of both sides it means that t has no value as -1 has no square root

and

t^2+7=0

t^2=-7

taking square root of both sides it means that t has no value as -7 has no square root

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