Description
A target lies flat on the ground 4 m from the side of a building that is 10 m tall.The acceleration of gravity is 10 m/s^2 . Air resistance is negligible. A student rolls a 4kg ball off the horizontal roof of the building in the direction of the target. The horizontal speed v with which the ball must leave the roof if it is to strike the target
is most nearly what
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mgsin tita
4x10 x0.0436
1.77
10^2 + 4^2
100+16
=116
squareroot of 116
10.77 meters
v^2=u^2-2gs
0=u^2-2 x 10 x10.77
u^2=215.4
u=14.68m/s
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