An artillery shell is ﬁred at an angle of 65.5◦ above the horizontal ground with an initial speed of 1520 m/s.The accelerationof gravity is 9.8 m/s^2.Find the total time of ﬂight of the shell, neglecting air resistance.Answer in units of min.
five decimal places
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initial speed= 1520 meters=1 second
acceleration gravity=9.8meters=1 second^2
time =distance /speed=1520/9.8=155.10204seconds
what would be the answer in minutes?
the answer is 155.10204/60=2.585minutes
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