An artillery shell is ﬁred at an angle of 65.5◦ above the horizontal ground with an initial speed of 1520 m/s.The accelerationof gravity is 9.8 m/s^2.Find the total time of ﬂight of the shell, neglecting air resistance.Answer in units of min.

five decimal places

Thank you for the opportunity to help you with your question!

initial speed= 1520 meters=1 second

acceleration gravity=9.8meters=1 second^2

time =distance /speed=1520/9.8=155.10204seconds

what would be the answer in minutes?

the answer is 155.10204/60=2.585minutes

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