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Jun 19th, 2015

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$\\ 7b^5-4b^3+2b =b(7b^4-4b^2+2)=b(7(b^2)^2-4(b^2)+2)$

Let $y=b^2$

Then the equation $7(b^2)^2-4(b^2)+2$ becomes $7y^2-4y+2$ which is a quadratic equation.

ANSWER:  $b(7(b^2)^2-4(b^2)+2)$

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Jun 19th, 2015

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