The temperature of a iron bar rises by 10.0°C when it absorbs 2.35 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of iron from these data.

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Specific Heat is the quantity of heat required to raise a gram of any substance by 1 degree Celsius.

Specific Heat formula is given by

C=∆Q/m∆T

where Δ Q is the heat gained or lost,

Δ T is the temperature difference.

Temperature difference is given by Δ T = (Tf - Ti), where Tf is the final temperature and Ti is the initial temperature.

Given:∆T=10.0°C

∆Q=2.35kJ =2.35*10^3 J

m=525g=0.525kg

C=2.35*1000/0.525*10

=2.35*1000/5.25

=447.61904 J/kg°C

Hence,specific heat of iron according to the above data is 447.61904 J/kg°C.

wrong

The answer is correct.Please check on the following website and specify where the mistake lies.

calculator.tutorvista.com/specific-heat-calculator.html?view=simple

http://www.endmemo.com/physics/specificheat.php

Answer can also be written in J/g°C.

Then,the specific heat value will be 0.44761 J/g°C.

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html#c2

Check on this site also.

The temperature of a silver bar rises by 10.0 Co when it absorbs 1.23 kJ of heat. The mass of the bar is 525 g. Determine the specific heat of silver.

Q = c m ∆T

c = Q / m ∆T

c = (1.23 x 10^3 J)/[(0.525 kg)(10 °C)]

c = 234 J/kg-°C

The above solved problem is available on this website

http://www.ux1.eiu.edu/~cfadd/1360/20Heat/HmwkSol.html

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