The temperature of a iron bar rises by 10.0°C when it absorbs 2.35 kJ of energy

Physics
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The temperature of a iron bar rises by 10.0°C when it absorbs 2.35 kJ of energy by heat. The mass of the bar is 525 g. Determine the specific heat of iron from these data.

Jun 19th, 2015

Thank you for the opportunity to help you with your question!

Specific Heat is the quantity of heat required to raise a gram of any substance by 1 degree Celsius.


Specific Heat formula is given by

C=∆Q/m∆T

where Δ Q is the heat gained or lost,

Δ T is the temperature difference.


Temperature difference is given by Δ T = (Tf - Ti), where Tf is the final temperature and Ti is the initial temperature.


Given:∆T=10.0°C

∆Q=2.35kJ =2.35*10^3 J

m=525g=0.525kg

C=2.35*1000/0.525*10

   =2.35*1000/5.25

   =447.61904 J/kg°C

  Hence,specific heat of iron according to the above data is 447.61904 J/kg°C.


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Jun 19th, 2015

wrong


Jun 19th, 2015

The answer is correct.Please check on the following website and specify where the mistake lies.


Jun 20th, 2015


Jun 20th, 2015

calculator.tutorvista.com/specific-heat-calculator.html?view=simple

Jun 20th, 2015

Answer can also be written in J/g°C.

Then,the specific heat value will be 0.44761 J/g°C.

Jun 20th, 2015

 

The temperature of a silver bar rises by 10.0 Co when it absorbs 1.23 kJ of heat. The mass of the bar is 525 g. Determine the specific heat of silver.

Q = c m ∆T

c = Q / m ∆T


c = (1.23 x 10^3 J)/[(0.525 kg)(10 °C)]


c = 234 J/kg-°C


 

Jun 20th, 2015

The above solved problem is available on this website

http://www.ux1.eiu.edu/~cfadd/1360/20Heat/HmwkSol.html


Jun 20th, 2015

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