##### Find the probability

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Four families get together for a barbecue. Every member of each family puts his or her name in a hat for a prize drawing. The Martell family has three members, the Werner family five, the Borschowa family four, and the Griffith family six. Two names are drawn from the hat. Find the probability of selecting two members from the same family

Jun 20th, 2015

Thank you for the opportunity to help you with your question!

The probability of selecting 2 members from the Martell family is

pM= 2C3/2C18 (the total number of members is 18)

so pM=3/153

You have also for the Werner family :

pW=2C5/2C18=10/153

for the Borshowa family :

pB=2C4/2C18=6/153

and finally for the Griffith family :

pG=2C6/2C18=15/153

We have to add all these probabilities to have the proba of selecting 2 members of a same family so :

p=34/153=0.222

Hope it helps

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 20th, 2015

These are the possible answers: a. 82/153, b. 2/51, c. 2/9, d. 7/9, e. 1/9

Jun 20th, 2015

34/153=2/9 also the right answer is c.

Jun 20th, 2015

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Jun 20th, 2015
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Jun 20th, 2015
Dec 9th, 2016
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