How do You find the molarity of Sodium hydroxide (NaOH) after doing a titration?

Chemistry
Tutor: None Selected Time limit: 1 Day

I know molarity is found by using moles/grams. I just don't know how to use my titration data to find those things. 298 drops of NaOH titrated the potassium hydrogen pthylate (KHP). We used 360 drops in all and 25.45 mL from the buret and calculated that one drop was equal to 0.0793.

Jun 20th, 2015

Thank you for the opportunity to help you with your question!

  first find the # of moles of NaOH.

since M = moles/Litres, what you do here is divide 25.45 ml by 1000 to get your volume units in Litres.

once you have the volume in litres, you multiply it by 0.20 M ( moles/litres ) thus cancelling the litres and giving you # moles of NaOH.

once that is done you can do a 1;1 stoichiometric ratio for your moles of OH- ( NaOH ) and H+ ( HCl ), giving you the moles of H+

and finally you divide the volume of HCl by 1000 to give you the volume units in litres and put moles of litres to find the molarity of HCl.


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 20th, 2015

Please what is the question

Jun 20th, 2015

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Jun 20th, 2015
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