simplify your answer.

Algebra
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(2w^2-8)/(w^2-w-2)

Jun 20th, 2015

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Jun 20th, 2015

ok thank you

Jun 20th, 2015

(2w^2-8)/(w^2-w-2)

=[2(w^2-4)] / (w^2-2w+w-2)

=[2(w^2-2^2)] / [w(w-2)+1(w-2)]

=[2(w+2)(w-2)] / [(w-2)(w+1)]

w-2 shall be cancelled

=2(w+2) / (w+1)



Jun 20th, 2015

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Jun 22nd, 2015

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