simplify your answer.

Algebra
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(3w^2+24w+21)/(w^2+12w+35)

Jun 21st, 2015

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Jun 21st, 2015

(3w^2+24w+21)/(w^2+12w+35)

=[3(w^2+8w+7)] / (w^2+12w+35)

=[3(w^2+7w+w+7)] / (w^2+5w+7w+35)

=3[w(w+7)+1(w+7)] / [w(w+5)+7(w+5)]

=3[(w+7)(w+1)] / [(w+5)(w+7)]

by canceling w+7

=3(w+1) / (w+5)

Best of Luck




Jun 21st, 2015

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