(3x-3)/(x^2+4x+3)*(x^2+x-6)/(x-1)

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3(x-1)/(x^2 +3x +x+3)*(x^2+x-6)/(x-1)

3(x-1)/(x(x+3)+(x+3))*(x^2+x-6)/(x-1)

3(x-1)/(x+1)(x+3)*(x^2+x-6)/(x-1)

3/(x+3)*(x^2+x-6)/(x-1)

3/(x+3)*(x^2+3x-2x-6)/(x-1)

3/(x+3)*(x(x+3)-2(x+3))/(x-1)

3/(x+3)*(x-2)(x+3)/(x-1)

3(x-1)/(x+3)*(x-2)(x+3)

3(x-1)/(x+3)(x-2)(x+3)

checking if i can simply it furthur.

we shall move step by step

ok i understand why you have squared the 2

we factor out 3 because it is common

so it should be 3x-1 maybe

no

(3x-3) we factor out 3 we get 3(x-1)

ok thank you for your help i think i will manage from this point, thanks!

if you are not sure please let me know

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