##### A 62-kg cross-country skier glides over snow as in the figure below.

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A 62-kg cross-country skier glides over snow as in the figure below. The coefficient of friction between skis and snow is 0.16. Assume all the snow beneath her skis is at 0°C and that all the internal energy generated by friction is added to snow, which sticks to her skis until it melts. How far would she have to ski to melt 2.5 kg of snow?

Oct 18th, 2017

Thank you for the opportunity to help you with your question!

mass=62 kg

friction coefficient =0.16

Q=mL

L-latent heat for ice=3*10^5 j/kg

Q=2.5*3*10^5

Q=7.5*10^5 j

so the friction energy can find as fallows

W=Fs-------------(1)

but

F=friction coefficient* R

R-the reactant force

so

F=0.16*62*9.81

F=97.32N

subustitute for (1)

W=97.32*S

but W=work=Q

so W=Q=7.5*10^5j

then

7.5*10^5=97.32*S

s=7.5*10^5/97.32

s=7706.5 m

so she has to ski 7706.5 m

Jun 21st, 2015

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Oct 18th, 2017
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Oct 18th, 2017
Oct 19th, 2017
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