In a period of 0.9 s, 5.0 10^{23} nitrogen molecules strike a wall of area 9.0 cm^{2}. If the molecules move at 280 m/s and strike the wall head on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N_{2} molecule is 4.68 10^{-26} kg.)

Thank you for the opportunity to help you with your question! the solution is as such:

On the basis of kinetic theory of gases, The pressure on the wall produced by the impact of these molecules is :

p= n*m*v ^2

where n is the no of molecules, m is the mass of the molecule and v is its velocity in the given direction.

so, total pressure exerted by the molecules is: p= 5.0* 10^23 * 4.68* 10 ^ -26 * (280)^2 so p= 1834.5 pascals
the ^ symbol stands for raised to the power.

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