A 78-kg cross-country skier glides over snow as in the figure below. The coeffic

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Jun 21st, 2015

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Jun 21st, 2015

Since the snow must melt, it goes through a phase change (occurring at 0°C), so the energy that must be added to convert a mass of snow into liquid water at 0°C is : 

Q = mL(f) 
= (1.00kg)(3.33 x 10^5J/kg) 
= 3.33 x 10^5J 

The force of kinetic friction is : 

f(k) = μ(k)mg 

The work done by friction when the skier moves through a displacement Δx is : 

|W(f)|= f(k)Δx 

If all the work done by friction is added to the snow in the form of internal energy, then the distance the skier must move through to melt 1.0kg of snow is : 

|W(f)| = f(k)Δx = Q 
Δx = Q / μ(k)mg 
= 3.33 x 10^5J / (0.22 x 78kg x 9.8m/s²) 
= 1980 m 

Jun 21st, 2015

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Jun 21st, 2015
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Jun 21st, 2015
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