A 78-kg cross-country skier glides over snow as in the figure below. The coeffic

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Jun 21st, 2015

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Jun 21st, 2015

The rate of cooling (as such by Newton) is given as = KA(t1 - t2)/d 
(Use 0.6 J/s · m · °C for the thermal conductivity of water.) 

where K= thermal conductivity 
A = area of cross section 
d = depth 
t1-t2 = temperature difference 

therefore rate of cooling = 0.6 x 860 x (25-12)/2.8 J/s = 2395.7 W 


Jun 21st, 2015

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