A 78-kg cross-country skier glides over snow as in the figure below. The coeffic

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Jun 21st, 2015

Dear your question is under-progress, it would be available to you as soon as it completes within next few minutes.


Jun 21st, 2015

The rate of cooling (as such by Newton) is given as = KA(t1 - t2)/d 
(Use 0.6 J/s · m · °C for the thermal conductivity of water.) 

where K= thermal conductivity 
A = area of cross section 
d = depth 
t1-t2 = temperature difference 

therefore rate of cooling = 0.6 x 860 x (25-12)/2.8 J/s = 2395.7 W 


Jun 21st, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jun 21st, 2015
...
Jun 21st, 2015
Jun 28th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer