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The rate of cooling (as such by Newton) is given as = KA(t1 - t2)/d (Use 0.6 J/s · m · °C for the thermal conductivity of water.) where K= thermal conductivity A = area of cross section d = depth t1-t2 = temperature difference
therefore rate of cooling = 0.6 x 860 x (25-12)/2.8 J/s = 2395.7 W
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