Description
(a) An ideal gas occupies a volume of 1.8 cm3 at 20°C and atmospheric pressure. Determine the number of molecules of gas in the container.
molecules(b) If the pressure of the 1.8-cm3 volume is reduced to 2.4 ✕ 10−11 Pa (an extremely good vacuum) while the temperature remains constant, how many moles of gas remain in the container?
mol
Explanation & Answer
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a)
PV = nRT
n = PV/RT
P = 1.00 atm
V = 1.8 cm³ = 1.8 cm³ x (1 mL / 1 cm³) x (1 L / 1000 mL) = 0.0018 L
R = 0.0821 Latm/moleK
T = 20C = 20+273.15 = 293.15K
n = (1.00 atm) x (0.0018 L) / [ (0.0821 Latm/moleK) x (293.15K) ]
n = 7.48x10^-5 moles..
finally...
7.48x10^-5 moles x (6.022x10^23 molecules / 1 mole) = 4.50x10^19 molecules.
you should probably only have 2 sig figs since 1.8 has 2 and 20 has at most 2...so call the final answer....
= 4.5x10^19 molecules
b) N = 1.6×10⁻¹¹ Pa ∙ 2.4×10⁻⁶ m³ / (1.38065 ×10⁻²³J/K ∙ 293.15K) = 9488
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