An ideal gas occupies a volume of 2.6 cm3 at 20°C and atmospheric pressure. Dete

Physics
Tutor: None Selected Time limit: 1 Day

Jun 21st, 2015

Dear your question is under-progress, it would be available to you as soon as it completes within next few minutes.


Jun 21st, 2015

Note: for this equation, as with most others, convert centimeters to meters. A is area, ΔT is change in temperature, and the Δx's represent the thicknesses (there are 3 for the 3 layers of glass, air, glass.) K is the thermal conductivity of a particular substance that you can find onhttp://en.wikipedia.org/wiki/Thermal_con... Your book/teacher may have listed a different number for this, and I have seen many variations (but trusted wikipedia) so you probably should have looked it up in the current chapter and listed the K.. 

A = 1.55 m^2 
ΔT = 22.6°C 
Δ1x = .50 cm = .005 m 
Δ2x = 1.0 cm = .01m 
Δ3x = .50 cm = .005 m 
K1 = .025 
k2 = 1.1 
K1 = .025 

First, multiply A by ΔT to get 35.03. Then divide this by number by .005/1.1 + .01/.025 + .005/1.1. I ended up with 71 J/s. 

For the single pane window, just plug into this equation: 
J/s (Single pane window) = -KA(ΔT/Δx) = -(1.1)(1.55)(-22.6/.01) = 3853 J/s 

Therefore, using significant digits: 
J/s (Thermopane window) = 71 J/s 
J/s (Single pane window) = 3853 J/s 
The thermopane window transfers a lot less heat per second than the single window, so it is a better insulator.

Jun 21st, 2015

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Jun 21st, 2015

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