The following problem refers to strings in A, B, ..., Z.

Mathematics
Tutor: None Selected Time limit: 1 Day

Jun 21st, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

the no of strings that begin with S can be shown as such: s_ _ _ .

now in these three blank spaces we can place any of  the 26 alphabets (A,B,C......Z) at each place, so the no. of ways using permutation is 26* 26*26=  17576

Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. thank you.
Jun 21st, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Jun 21st, 2015
...
Jun 21st, 2015
May 30th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer