At what temperature would the rms speed of carbon dioxide molecules equal the fo

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Jun 21st, 2015

Thank you for the opportunity to help you with your question!

We use the formula v^2 = 3RT/M for calculating the rms speed in both questions:

(a) v^2 = 3RT/M, where v is the escape speed from Earth

(1.12 x 104)= (3 x 8.314 x T)/(44.01) 

 T = 2.21 x 108 Kelvins

(b) v^2 = 3RT/M, where v is the escape speed from the Moon

(2.37 x 103)2 = (3 x 8.314 x T)/(44.01)
  

 T = 9.91 x 106 Kelvins 


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 21st, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Jun 21st, 2015
...
Jun 21st, 2015
Oct 22nd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer