At what temperature would the rms speed of carbon dioxide molecules equal the fo

Physics
Tutor: None Selected Time limit: 1 Day

Jun 21st, 2015

Thank you for the opportunity to help you with your question!

We use the formula v^2 = 3RT/M for calculating the rms speed in both questions:

(a) v^2 = 3RT/M, where v is the escape speed from Earth

(1.12 x 104)= (3 x 8.314 x T)/(44.01) 

 T = 2.21 x 108 Kelvins

(b) v^2 = 3RT/M, where v is the escape speed from the Moon

(2.37 x 103)2 = (3 x 8.314 x T)/(44.01)
  

 T = 9.91 x 106 Kelvins 


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Jun 21st, 2015

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