Description
A plane is flying horizontally with speed
217m/s at a height 4840 m above the ground when a package is dropped from the plane.
The acceleration of gravity is 9.8 m/s^2. the horizontal distance from the
release point to the impact point is 6820 m.
A second package is thrown downward from
the plane with a vertical speed v1 = 56 m/s.
Whats the magnitude of the total velocity
of the package at the moment it is thrown. Answer in m/s. Round 5 decimal places
Explanation & Answer
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4840=(x*0.175)+(0.5*9.8*0.175^2)
the magnitude is 122m/s
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