need help with word problems

Mathematics
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the length of a rectangle is 3 yd longer than is width if the perimeter of the rectangle is 46 yd, find its area.

Jun 22nd, 2015

Hi !

width = x

length = 3 + x

perimeter = 46 yards

area = ?

As 

Perimeter = 2(width + length)

46  = 2(x + 3 + x)

46  = 2x + 6 + 2x

46 = 4x + 6

4x + 6 - 6 = 46 - 6

4x = 40

4x / 4 = 40 / 4

x = 10 yd

width = x = 10 yd

length = 3 + x = 3 + 10 = 13 yd

Now 

Area = width * length

         = 10 * 13

         = 130 yd^2

Hence the area is 130 yd^2

Did you get it?

Hope you get it. Thanks :)
Jun 22nd, 2015

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