At what temperature would the rms speed of carbon dioxide molecules equal the fo

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Jun 22nd, 2015

Thank you for the opportunity to help you with your question!

The rms speed of particular particles in a certain gas is given by the formula;

Vrms = sqrt [(3RT/M) where R is 8.3145 (kg·m2/sec2)/K·mol, T is temperature in Kelvin and M is mass of a mole of the gas in kilograms.

Solving for T, will result to the equation changing to;

T= Vrms^2*M/3R

Thus,

a) T= [(1.12*10^4)^2*7.30*10^-26] / 3*8.3145

b) T= [(2.37*10^3)^2*7.30*10^-26] / 3*8.3145

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 22nd, 2015

I will be grateful if you could ask me any follow up questions. I would really appreciate it and help out accordingly.

Jun 22nd, 2015

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Jun 22nd, 2015
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Jun 22nd, 2015
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