In a sample of 50 women, it is determined that 53% have their HDL cholesterol level checked on a regular basis. Find the margin of error of a 95% confidence interval for the proportion of all such females
Dear your question is under-progress, it would be available to you as soon as it completes within next few minutes.
95% level of confidence. We want to look up thez-scorez*for which the area between -z* and z* is 0.95. From the table we see that this critical value is 1.96.
since α = 1 - 0.95 = 0.05, we see that α/2 = 0.025
We now search the table to find thez-score with an area of 0.025 to its right. We would end up with the same critical value of 1.96.
E = 1.96 / 2√ 50
E = 6.93
Please complete your pledge by rating at least 4 stars. Thanks in advance:)
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?