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Jun 23rd, 2015

60 minutes of minute hand rotation = 360°

therefore for 20° it will move 360 /60 *20 = 120° (answer 1)

(2) in one rotation (360°) traveled distance = 2 * pi * r = 2*3.14 *11 =69.08 cm

therefore for 120° distance traveled = 69.08/3 = 23.0266 cm (answer 2)

(3) for displacement vector find the distance between the starting tip point, and the end tip
point. Draw the minute hand at 3.00 and a minute hand at 3:20, join their
tips and notice that they form a triangle with angle 120° with legs
11 cm long.

To find the long side (the displacement magnitude), use cosine law:

c² = a² + b² - 2abcos(Θ)
c = √( 11² + 11² - 2(11)(11) cos(120°) ) c = 11 cm (answer 3)