The length of the minute hand on a clock is11cm.A) Through what angle did this hand turn between 3:00PM and 3:20PM? Answer in units of degrees

B) What distance was actually traveled by the tip of the minute hand during this time interval? Answer in units of cm.

C) What was the magnitude of the displacement vector of the minute hand’s tip during this time period ?Answer in units of cm

Thank you for the opportunity to help you with your question!

A. ) 1/3 0f 360 = 120 degrees

B) !/3 x 2π r = 1/3 x 2x 3.1416 x 11

= 23.0384 cm

C) 2 x 11 x sin 60 = 11 √3 = 19.0526 cm

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