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10^(logx-4) = e^((logx - 4)ln(10)) we know : log(x) = ln(x) / ln(10)
10^(logx-4) = e^((logx - 4)ln(10)) = e^((ln(x-4)/ln(10))*ln(10)) = e^(ln(x-4)) = x - 4
if you dont understand something let me know it
so it's x-4?
i dont know for this :
logx-4 is :
log(x) - 4 or log(x - 4)
if is log(x) - 4
the result is not x - 4
let me know please
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