10^(logx-4) = simplify

Algebra
Tutor: None Selected Time limit: 1 Day

10^(logx-4) = 

Jun 23rd, 2015

Thank you for the opportunity to help you with your question!

10^(logx-4) = e^((logx - 4)ln(10))  we know : log(x) = ln(x) / ln(10) 

so : 

10^(logx-4) = e^((logx - 4)ln(10))  =  e^((ln(x-4)/ln(10))*ln(10)) =  e^(ln(x-4)) = x - 4 


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Jun 23rd, 2015

so it's x-4?

Jun 23rd, 2015

yes 

but : 

i dont know for this : 

logx-4  is : 

log(x) - 4  or  log(x - 4)


if is log(x) - 4 

the result is not  x - 4 

let me know please 

Jun 23rd, 2015

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