10^(logx-4) =

Thank you for the opportunity to help you with your question!

10^(logx-4) = e^((logx - 4)ln(10)) we know : log(x) = ln(x) / ln(10)

so :

10^(logx-4) = e^((logx - 4)ln(10)) = e^((ln(x-4)/ln(10))*ln(10)) = e^(ln(x-4)) = x - 4

Good luck

my friend

if you dont understand something let me know it

so it's x-4?

yes

but :

i dont know for this :

logx-4 is :

log(x) - 4 or log(x - 4)

if is log(x) - 4

the result is not x - 4

let me know please

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