10^(logx-4) = simplify


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10^(logx-4) = 

Jun 23rd, 2015

Thank you for the opportunity to help you with your question!

10^(logx-4) = e^((logx - 4)ln(10))  we know : log(x) = ln(x) / ln(10) 

so : 

10^(logx-4) = e^((logx - 4)ln(10))  =  e^((ln(x-4)/ln(10))*ln(10)) =  e^(ln(x-4)) = x - 4 


Good luck 

my friend 

if you dont understand something let me know it 

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 23rd, 2015

so it's x-4?

Jun 23rd, 2015

yes 

but : 

i dont know for this : 

logx-4  is : 

log(x) - 4  or  log(x - 4)


if is log(x) - 4 

the result is not  x - 4 

let me know please 

Jun 23rd, 2015

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